Essentially the House version of this thread.
https://uselectionatlas.org/FORUM/index.php?topic=165782.0What if the parties were given house seats based on their percent of the House national popular vote? This would lead to third parties getting seats and often neither major party would get a majority to elect a speaker, forcing them to deal with other parties to get votes.
Take 2000.
| Party (2000) | % | Seats |
| Republican | 47.3 | 205.755 |
| Democrat | 47 | 204.45 |
| Other | 2.2 | 9.57 |
| Libertarian | 1.6 | 6.96 |
| Independent | 0.7 | 3.045 |
| Natural Law | 0.4 | 1.74 |
| Green | 0.3 | 1.305 |
| Independence | 0.2 | 0.87 |
| Reform | 0.2 | 0.87 |
| Constitution | 0.1 | 0.435 |
We have to round some parties up and some down to get exactly 435 seats. In 2000 we need to round 6 parties up, these parties are the ones with the largest decimals. The Libertarians, Independence, Reform, Republicans, Natural Law, and 'Other' all get an additional seat.
Republicans: 206
Democrats: 204
Other: 10
Libertarian: 7
Independent: 3
Natural Law: 2
Green: 1
Independence: 1
Reform: 1
Republicans would need to get 12 third party congressmen to get one of their own as speaker, Democrats would need 14.
The Green congressperson would support the Democrat while the Libertarians could probably be persuaded to vote for the Republican. The big wildcard are the 3 independents and 10 'others', each of those congressmen could be from pretty much any ideology. It looks like that the Republicans would be more likely to put together a coalition, though it would be a very interesting scenario.
