States where a county sweep for one party is likelier than the other party winning the state? (user search)
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  States where a county sweep for one party is likelier than the other party winning the state? (search mode)
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Author Topic: States where a county sweep for one party is likelier than the other party winning the state?  (Read 779 times)
Figueira
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« on: December 10, 2020, 12:13:06 PM »

Obviously Massachusetts, Rhode Island, Hawaii, West Virginia, and Oklahoma are a given.

Vermont
Connecticut
Delaware
Maryland(?)
Kentucky
Arkansas
Nebraska
North Dakota
Wyoming
Utah
Idaho

Anything I missed?
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Figueira
84285
Atlas Icon
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Posts: 12,173


« Reply #1 on: December 10, 2020, 02:45:23 PM »

Obviously Massachusetts, Rhode Island, Hawaii, West Virginia, and Oklahoma are a given.

Vermont
Connecticut
Delaware
Maryland(?)
Kentucky
Arkansas
Nebraska
North Dakota
Wyoming
Utah
Idaho

Anything I missed?

Louisiana, Alaska, Virginia, Missouri, Nevada.

A Democratic sweep of Nevada is more likely than a Republican win in the state? Huh

Also, totally agreed on whoever said California. Democrats winning places like Plumas/Lassen/Modoc is more likely than Republicans winning the state.
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Figueira
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Posts: 12,173


« Reply #2 on: December 10, 2020, 07:53:46 PM »

Maryland's only been fully swept once, by Eisenhower in 56. A Dem sweep is impossible because of Garrett County, part of the infamous school of German Unionist mid-Appalachian counties as seen in KY, TN, and WV, although a Dem sweep of every other county in the state has been done before, as by Mikulski in 92 and 98.

Yeah, Dems winning Garrett County and Rs winning Maryland are so impossible that it's hard to say which is more likely, but I think I'd go with Garrett County just because it's smaller and it's easier for a fluke to flip it. Similar stuff applies in North Dakota.
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