Do Dems get a "working majority"? (user search)
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  Do Dems get a "working majority"? (search mode)
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Poll
Question: Do Dems finish with.....
#1
Over 51.5 Senate seats?
 
#2
Under 51.5 Senate seats?
 
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Partisan results

Total Voters: 56

Author Topic: Do Dems get a "working majority"?  (Read 1679 times)
MT Treasurer
IndyRep
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Posts: 15,275
United States


« on: October 26, 2020, 01:32:02 PM »

Manchin and Sinema aren’t casting the deciding vote against the Democrats OR persuading the Senate Democratic leadership to abandon any legislation. A 50/50 Senate under a Biden presidency is a working majority.

It honestly baffles me how easily people get conned by Manchin and Sinema even after everything they’ve done since 2019.

Also, I suspect Greenfield will be Manchin/Sinema democrat.

You’re actually right, just not in the way you intended to be.
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MT Treasurer
IndyRep
Atlas Icon
*****
Posts: 15,275
United States


« Reply #1 on: October 26, 2020, 01:47:07 PM »

It is much easier to vote no on everything put forward by Republicans than spend political capital on reforms one's backers don't support.

Manchin has nothing to lose because he’ll more likely than not retire and Sinema couldn’t get away with being the leading voice/deciding vote of opposition to major Democratic policy proposals in a left-trending Biden state in which there’s no shortage of credible primary challengers. She could pull that stunt/put on a show in a 51D-49R Senate, but certainly not a 50R-50D Senate.

What reforms contrary to the backers' interests are we talking about here, and who are the backers in this case? I don’t think ultra-wealthy "backers" of Sinema are all that different from or more opposed to expanding the court or nuking the filibuster (to give just one example) than Schumer's backers.
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