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  Talk Elections
  Presidential Elections - Analysis and Discussion
  U.S. Presidential Election Results (Moderators: Torie, ON Progressive)
  1892: Cleveland wins, but not on 5 state ballots?
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Author Topic: 1892: Cleveland wins, but not on 5 state ballots?  (Read 1147 times)
tinman64
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« on: September 02, 2005, 02:22:54 am »

Here's something I've always wondered about...

Grover Cleveland returned to the White House, elected in 1892 after being turned out in 1888.  Despite a comfortable victory, he received no votes in 5 states: Colorado, Idaho, Kansas, North Dakota and Wyoming.

I suspect this could be due to the Democratic state parties supporting the Populist James Weaver, and leaving Cleveland off the ballot.  Weaver did very well in all 5 states.  However, Cleveland received votes in other states where Weaver did well, including Montana, Nebraska, Nevada, Oregon, South Dakota, and Washington.

Does anyone know why Cleveland did not receive votes in these 5 states?
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jfern
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« Reply #1 on: September 03, 2005, 03:15:58 am »

North Dakota got off to a good start by having 1 elector for the Democrat, 1 for the Republican, and 1 for the Populist.
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jimrtex
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« Reply #2 on: September 03, 2005, 03:17:30 am »

In the Colorado gubernatorial race in 1892, the Democrat finished a poor 3rd:

Populist 44,242
Republican 38,620
Democrat 8,944
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Erc
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« Reply #3 on: September 04, 2005, 03:51:32 pm »

Cleveland was a Gold Democrat.

He thus pissed off the Republicans by being a Democrat.

And he pissed off the Silverites by supporting Gold.

So the populists got the traditional Democratic support in these states...which, of course, got reabsorbed in 1896 with the Populist-Democrat fusion under Bryan (just look at the Nevada '96 results).

Bryan ended up retaking the West from the Populists...but lost the cities in the process.  If I remember correctly, the largest city to vote for him was Troy, NY...
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