US with UK seats - Creating 650 seats
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  US with UK seats - Creating 650 seats
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Author Topic: US with UK seats - Creating 650 seats  (Read 1408 times)
afleitch
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« on: January 10, 2012, 07:50:43 AM »

Taking inspiration from the Canadian topic Cheesy

There are two ways I could do this. Firstly I could have one seat for approximately 70,000 voters. This of course has happened by chance; the number of seats in the UK has stayed broadly the same even as the electorate has increased. Instead I have divided the total adult population (18+) of the USA by 650 to give an electorate. This is making an assumption that voter registration in the US is higher than it is in reality.

So 234,646,600 divided by 650 = 360,995

The Boundary Comissions are usually happy with between a 5% and 10% variance

So 5% variance 342,946 - 379,045
    10% variance 324,896 - 397,095

For the purposes of this exercise, state boundaries will not be crossed. For those familiar with the Boundary Comissions work, in this exercise States will be treated similar to Counties and US Counties similar to Districts

So here we go. Staring with the Eastern Seaboard

Maine - 2.92 = 3
New Hampshire - 2.85 = 3
Vermont - 1.37 = 1 or 2
(Note: If state lines could be crossed a case could be made for a Vermont and New Hampshire to be allocated 4 seats between them)
Massachussets - 14.2 = 14
Rhode Island - 2.29 = 2
Connecticut - 7.63 = 8
New York - 41.7 = 42
Pennsylvania - 27.45 = 27
New Jersey - 18.63 = 19
Delaware - 1.92 = 2
Maryland - 12.25 = 12
District of Columbia - 1.39 = 1 or 2
West Virginia - 4.07 = 4
Virginia - 17.02 = 17
North Carolina - 20.10 = 20
South Carolina - 9.81 = 10
Georgia - 19.94 = 20

And for the record, California would be entitled to 77 seats
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Antonio the Sixth
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« Reply #1 on: January 10, 2012, 08:23:12 AM »

Interestingly, this number is close to the ideal seat number for the USA based on the cube root rule (676).
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afleitch
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« Reply #2 on: January 10, 2012, 12:56:43 PM »

Interestingly, this number is close to the ideal seat number for the USA based on the cube root rule (676).

Well spotted Wink
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Teddy (IDS Legislator)
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« Reply #3 on: January 10, 2012, 06:30:08 PM »

Cube Root Rule??? Now this is very interesting. How does it work exactly?
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afleitch
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« Reply #4 on: January 10, 2012, 07:56:49 PM »

Cube Root Rule??? Now this is very interesting. How does it work exactly?

Is is the theory that an assembly or parliament should have a number of members equal to the cube root of the number being represented. In the US, that would be 676 on 2010 Census numbers.

It works for all sizes. The cube root of the Scottish electorate is 158 for example.
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