1988: Bentsen/Graham vs. Bush/Quayle
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  1988: Bentsen/Graham vs. Bush/Quayle		 « previous next »
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Author Topic: 1988: Bentsen/Graham vs. Bush/Quayle  (Read 2694 times)
Thomas D
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« on: December 08, 2010, 08:40:27 PM »
Lloyd Bentsen/ Bob Graham
George Bush/ Dan Quayle

I was trying to think of how the Democrats could have at least come close to winning in 1988 and this is what I came up with. So Who wins?

Discuss. With maps if doing so would please you. Wink
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Cathcon
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« Reply #1 on: December 08, 2010, 08:59:31 PM »
Who wins Texas? I think it would most likely be Bentsen given the facts that Texas voted for him over Bush in 1970, Bush was rejected by Texas twice, and that Bentsen won election three times.
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Thomas D
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« Reply #2 on: December 08, 2010, 09:20:35 PM »


Bentsen 277-261
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Fuzzybigfoot
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« Reply #3 on: December 08, 2010, 09:37:37 PM »

I would add New Mexico too.  Dukakis only lost it by 5%, and he was a much weaker candidate than Bentsen.  Maybe Louisiana, Kentucky, and Ohio too.
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Lincoln Republican
Winfield
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« Reply #4 on: December 08, 2010, 09:48:09 PM »
The absolute electoral ceiling for Bentsen in 1988.  I do not believe he could have done any better than this, and likely not this well.

Bush/Quayle            298
Bentsen/Graham       240



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Kaine for Senate '18
benconstine
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« Reply #5 on: December 19, 2010, 05:57:17 PM »

284 - 254
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Sec. of State Superique
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« Reply #6 on: May 12, 2013, 01:30:58 PM »

WTF Vermont?
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Thomas D
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« Reply #7 on: May 13, 2013, 04:42:33 PM »
« Edited: May 13, 2013, 07:26:49 PM by Thomas D »
Bush had roots in New England so I think there's a good chance it (Vermont) would go for him over Bentsen
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Oldiesfreak1854
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« Reply #8 on: May 16, 2013, 07:34:43 AM »

Vice Pres. George H. W. Bush (R-TX)/Sen. Dan Quayle (R-IN): 373
Sen. Lloyd Bentsen (D-TX)/Sen. Bob Graham (D-FL): 165
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shua
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« Reply #9 on: May 17, 2013, 01:52:21 AM »


Bush/Quayle: 304, 52%
Bentsen/Graham: 234, 47%
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