2012: Romney/McDonnell (R) vs. Obama/Biden (D) vs. Roemer/Bowles (I/AE)
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  2012: Romney/McDonnell (R) vs. Obama/Biden (D) vs. Roemer/Bowles (I/AE)
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Poll
Question: Who would you vote for?
#1
Obama (D)
 
#2
Obama (R)
 
#3
Obama (I)
 
#4
Romney (D)
 
#5
Romney (R)
 
#6
Romney (I)
 
#7
Roemer (D)
 
#8
Roemer (R)
 
#9
Roemer (I)
 
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Partisan results

Total Voters: 25

Author Topic: 2012: Romney/McDonnell (R) vs. Obama/Biden (D) vs. Roemer/Bowles (I/AE)  (Read 1237 times)
Snowstalker Mk. II
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« on: December 26, 2011, 07:32:32 PM »

Forgot about AE, didn't you?
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Pheurton Skeurto
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« Reply #1 on: December 26, 2011, 07:39:34 PM »

Roemer (I)
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Oakvale
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« Reply #2 on: December 26, 2011, 07:46:59 PM »


Yes, and with good reason because it's a complete joke.

Why would someone fairly respected like Erskine Bowles join a ticket with Roemer on it?
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Snowstalker Mk. II
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« Reply #3 on: December 26, 2011, 07:48:44 PM »

It probably is, but...let's say Roemer gets the Paul endorsement.
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DrScholl
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« Reply #4 on: December 26, 2011, 07:49:01 PM »


Yes, and with good reason because it's a complete joke.

Why would someone fairly respected like Erskine Bowles join a ticket with Roemer on it?

Yes, I was thinking the same thing. It would make no sense for Bowles to do that.
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Oakvale
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« Reply #5 on: December 26, 2011, 07:50:20 PM »

Here are what the results would look like, in my expert opinion -

Obama/Biden: Somewhere between 45% and 55%
Romney/McDonnell: Somewhere between 45% and 55%
Roemer/Bowles: Between 2% and 3%
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TheGlobalizer
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« Reply #6 on: December 26, 2011, 08:52:57 PM »

Here are what the results would look like, in my expert opinion -

Obama/Biden: Somewhere between 45% and 55%
Romney/McDonnell: Somewhere between 45% and 55%
Roemer/Bowles: Between 2% and 3%


Dude, you should totally buy a lottery ticket.
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