Who is more likely to win?
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Poll
Question: Who has a better chance of winning?
#1
Scott Walker (WI gov. race)		  
#2
Richard Cordray (OH gov. race)		  
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Partisan results
Total Voters: 41

Author Topic: Who is more likely to win?  (Read 542 times)
Scottholes 2.0
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« on: October 31, 2018, 03:37:00 PM »
According to the Classic 538 forecast, Richard Cordray has a 48 percent chance of winning, while Scott Walker has a 42 percent chance of winning, which is interesting because he's an incumbant.

My take: Scott Walker just because of his incumbancy. I think Evers is slightly more likely to win than Walker, but the latest MU poll does concern me, which means that I need to do as much canvassing as I can before Election Day!
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Lechasseur
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« Reply #1 on: October 31, 2018, 03:47:55 PM »
Frankly I think both will lose, but I agree with the OP.
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bagelman
Junior Chimp
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« Reply #2 on: October 31, 2018, 04:30:44 PM »
Cordray is at 55-60% in my book, while Walker tops out at 40%.
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ElectionsGuy
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« Reply #3 on: October 31, 2018, 04:34:17 PM »
I think Cordray basically has a 50/50 chance with DeWine while Walker is a slight underdog at 40-45% chance.
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andjey
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« Reply #4 on: November 01, 2018, 01:57:57 AM »
Quote from: ElectionsGuy on October 31, 2018, 04:34:17 PM
I think Cordray basically has a 50/50 chance with DeWine while Walker is a slight underdog at 40-45% chance.
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Politician
Junior Chimp
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« Reply #5 on: November 01, 2018, 06:37:14 AM »
Quote from: VOTE FOR PHIL BREDESEN on 6th November on November 01, 2018, 01:57:57 AM
Quote from: ElectionsGuy on October 31, 2018, 04:34:17 PM
I think Cordray basically has a 50/50 chance with DeWine while Walker is a slight underdog at 40-45% chance.
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