Title: 1892: Cleveland wins, but not on 5 state ballots? Post by: tinman64 on September 02, 2005, 02:22:54 AM Here's something I've always wondered about...
Grover Cleveland returned to the White House, elected in 1892 after being turned out in 1888. Despite a comfortable victory, he received no votes in 5 states: Colorado, Idaho, Kansas, North Dakota and Wyoming. I suspect this could be due to the Democratic state parties supporting the Populist James Weaver, and leaving Cleveland off the ballot. Weaver did very well in all 5 states. However, Cleveland received votes in other states where Weaver did well, including Montana, Nebraska, Nevada, Oregon, South Dakota, and Washington. Does anyone know why Cleveland did not receive votes in these 5 states? Title: Re: 1892: Cleveland wins, but not on 5 state ballots? Post by: ○∙◄☻¥tπ[╪AV┼cVê└ on September 03, 2005, 03:15:58 AM North Dakota got off to a good start by having 1 elector for the Democrat, 1 for the Republican, and 1 for the Populist.
Title: Re: 1892: Cleveland wins, but not on 5 state ballots? Post by: jimrtex on September 03, 2005, 03:17:30 AM In the Colorado gubernatorial race in 1892, the Democrat finished a poor 3rd:
Populist 44,242 Republican 38,620 Democrat 8,944 Title: Re: 1892: Cleveland wins, but not on 5 state ballots? Post by: Erc on September 04, 2005, 03:51:32 PM Cleveland was a Gold Democrat.
He thus pissed off the Republicans by being a Democrat. And he pissed off the Silverites by supporting Gold. So the populists got the traditional Democratic support in these states...which, of course, got reabsorbed in 1896 with the Populist-Democrat fusion under Bryan (just look at the Nevada '96 results). Bryan ended up retaking the West from the Populists...but lost the cities in the process. If I remember correctly, the largest city to vote for him was Troy, NY... |