Sanders's path (or lack thereof) to victory (from 538) (user search)
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  Sanders's path (or lack thereof) to victory (from 538) (search mode)
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Author Topic: Sanders's path (or lack thereof) to victory (from 538)  (Read 1150 times)
IceSpear
Atlas Superstar
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Posts: 31,840
United States


Political Matrix
E: -6.19, S: -6.43

« on: March 30, 2016, 10:41:38 PM »

A narrow Sanders win in Wisconsin would be devastating to his chances of reaching a majority of pledged delegates.

Nah, that's wishful thinking. Since CA unfortunately votes dead last, the goalposts can and will be moved. "We just need to win CA by 20. No, 30. Actually, 40. Make that 50..."

Well, that's assuming you're planning on convincing the diehards. To the non diehards (and many of the more realistic diehards), his chances are already devastated.
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IceSpear
Atlas Superstar
*****
Posts: 31,840
United States


Political Matrix
E: -6.19, S: -6.43

« Reply #1 on: March 30, 2016, 11:02:13 PM »

Clinton did win Arizona, which is technically in the south, but more important a Republican state.
This "Clinton only wins safe R states" mantra needs to stop. She won Ohio, Massachusetts, Illinois, Virginia, Nevada, Florida, and Iowa, and is likely to win NY/PA/MD/DE.

Yeah, it's quite interesting this narrative is still around when you look at the facts. I'll define a safe R state as a state that has voted Republican in the last 4 elections.

Alabama, Arizona, Arkansas, Georgia, Louisiana, Mississippi, Missouri, South Carolina, Tennessee, Texas

Alaska, Idaho, Kansas, Nebraska, Oklahoma, Utah

Kentucky, Montana, North Dakota, South Dakota, West Virginia, Wyoming


Assuming Bernie sweeps MT/ND/SD/WY as is widely expected, they will be tied in safe R states, leaving WV/KY as deciders, states in which Bernie has a good chance to win. If anything, this gets even more favorable to Hillary if you exclude states like GA/AZ/MO from the safe R designation. Regardless, Bernie may very well end up winning a majority of safe R states. Ironic.
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